Are any of these three problems identities? 1. Cos^2xsin^2x=12sin^2x 2. Sinxsecx=cosxcscx 3. Sec^4xtan^4/sec^2x=1+sin^2x If so, how can you conclude that any of them are identities?
19,255 results
Trigonometry
How do you verify the equation is an identity? Tan^2xtan^2y=sec^2xsec^2y and, how do you factor and simplify, cscx(sin^2x+cos^2xtanx)/sinx+cosx

solving trig. equations
tan(3x) + 1 = sec(3x) Thanks, pretend 3x equals x so tanx + 1 = secx we know the law that 1 + tanx = secx so tanx + 1 becomes secx and... secx = secx sec(3x) = sec(3x) [just put 3x back in for x you don't really have to change 3x to x but it kinda makes

Precalculus check answers help!
1.) Find an expression equivalent to sec theta sin theta cot theta csc theta. tan theta csc theta sec theta ~ sin theta 2.) Find an expression equivalent to cos theta/sin theta . tan theta cot theta ~ sec theta csc theta 3.) Simplify (tan^2 theta +

Precalculus help
I have two problems I am stuck on, if you could show me how to solve the problems it would be much appreciated. 1) Find sin 2x, cos 2x, and tan 2x from the given information. tan x = − 1/6, cos x > 0 sin 2x = cos 2x = tan 2x = 2) Find sin 2x, cos 2x, and

Math
Which of the following expressions is equivalent to (cos(3x))/sin(x)cos(x))? csc(x) cos(2x)  sec(x) sin(2x) sec(x) cos(2x)  csc(x) sin(2x) sec(x) cos(x)  csc(x) sin(x) csc(x) cos(x)  sec(x) sin(x) This is my last question and I've tried solving it

Precalculus
Circle O below has radius 1. Eight segment lengths are labeled with lowercase letters. Six of these equal a trigonometric function of theta. Your answer to this problem should be a six letter sequence whose letters represent the segment lengths that equal

Math:)
1. Simplify the expression. [csc^2(x1)]/[1+sin x] a. csc x+1 b. csc x(csc x1) c. sin^2 xcsc x**** d. csc^2 xcos xtan x 2. Which of the following expressions can be used to complete the equation below? sec x/1+cot^2 x a. tan x b. tan^2 x c. tan x cos x

Trig
Are any of these three problems identities? 1. Cos^2xsin^2x=12sin^2x 2. Sinxsecx=cosxcscx 3. Sec^4xtan^4/sec^2x=1+sin^2x If so, how can you conclude that any of them are identities?

Pre Calculus
Multiply; then use fundamental identities to simplify the expression below and determine which of the following is not equivalent. (sin x + cos x) ^2 a. 1+2sinxcosx b. sec^2x−tan^2x+2cosxsinx c.sec x + 2 sin x/sec x d. sin^2x+cos^2x e. 1+2cos (pi / 2 

Math
Use the given function value(s), and trigonometric identities(including the cofunction identities), to find the indicated trigonometric function. sec θ = 5 a) cos θ = 1/sec θ = 1/5 b) cot θ = cos θ/sin θ =cosθ/cos(90θ) I did a but im stuck for b,

math
Proving Trigonometric Identities 1. sec^2x + csc^2x= (sec^2 x)(csc^2 x) 2. sin ^3 x / sin x  cos 3x / cos x = 2 3. 1 cos x/ sin x= sin x/ 1+ cos x 4. 2 sin x cos ^2 (x/2) 1/x sin (2x) = sinx 5. cos 2 x + sin x/ 1 sin x= 1+ 2 sin x

Integration
Intergrate ¡ì sec^3(x) dx could anybody please check this answer. are the steps correct? thanks. = ¡ì sec x d tan x = sec x tan x  ¡ì tan x d sec x = sec x tan x  ¡ì sec x tan^2(x) dx = sec x tan x + ¡ì sec x dx  ¡ì sec^3(x) dx = sec x tan x

Precalculus
Use one of the identities cos(t + 2πk) = cos t or sin(t + 2πk) = sin t to evaluate each expression. (Enter your answers in exact form.) (a) sin(19π/4) (b) sin(−19π/4) (c) cos(11π) (d) cos(53π/4) (e) tan(−3π/4) (f) cos(π/4) (g) sec(π/6+ 2π)

Trig
Given: cos u = 3/5; 0 < u < pi/2 cos v = 5/13; 3pi/2 < v < 2pi Find: sin (v + u) cos (v  u) tan (v + u) First compute or list the cosine and sine of both u and v. Then use the combination rules sin (v + u) = sin u cos v + cos v sin u. cos (v  u) = cos u

PreCalculus
This question has me stuck. Use the Pythagorean identity sin^2 Θ + cos^2 Θ = 1 to derive the other Pythagorean identities, 1 + tan^2 Θ = sec^2 Θ and 1 + cot^2 Θ = csc^2 Θ. Discuss how to remember these identities and other fundamental identities.

math
prove these identies sin^2+tan^2=sec^2cos^2 sin^2 sec^2 +sin^2=tan^2+sin^2

math;)
Julia wants to simplify the term sec^2 theta1/cot^2 theta+1 in a trigonometric identity that she is proving. Which of the following identities should use to help her? Select all that apply. (2 ANSWERS) a. sin^2 theta+cos^2 theta=1 b. sec^2 thetatan^2

tigonometry
expres the following as sums and differences of sines or cosines cos8t * sin2t sin(a+b) = sin(a)cos(b) + cos(a)sin(b) replacing by by b and using that cos(b)= cos(b) sin(b)= sin(b) gives: sin(ab) = sin(a)cos(b)  cos(a)sin(b) Add the two equations:

TRIG..............
Q.1 Prove the following identities: (i) tan^3x/1+tan^2x + cot^3x/1+cot^2 = 12sin^x cos^x/sinx cosx (ii) (1+cotx+tanx)(sinxcosx)/sec^3xcosec^3x = sin^2xcos^2x.

Pre Calculus
Use one of the identities cos(t + 2ðk) = cos t or sin(t + 2ðk) = sin t to evaluate each expression. (Enter your answers in exact form.) (a) sin(17ð/4) (b) sin(−17ð/4) (c) cos(17ð) (d) cos(45ð/4) (e) tan(−3ð/4) (f) cos(7ð/4) (g) sec(ð/6+2ð)

trigonometry (please double check this)
Solve the following trig equations. give all the positive values of the angle between 0 degrees and 360 degrees that will satisfy each. give any approximate value to the nearest minute only. 1. sin2ƒÆ = (sqrt 3)/2 2. sin^2ƒÆ = cos^2ƒÆ + 1/2 3. sin 2x

trigonometry repost
Reduce (csc^2 x  sec^2 X) to an expression containing only tan x. (is this correct?) csc x = 1/sin x sec x = 1/cos x tan x = 1/cot x sin^2 x + cos^2 x = 1 1 + cot^2 x = csc^2 x tan^2 x + 1 = sec^2 x csc^2 x  sec^2 x = 1 + cot^2 x  (1 + tan^2 x) = cot^2

AP Calculus AB
2. For an object whose velocity in ft/sec is given by v(t) = t^2 + 6, what is its displacement, in feet, on the interval t = 0 to t = 3 secs? 3. Find the velocity, v(t), for an object moving along the xaxis if the acceleration, a(t), is a(t) = cos(t) 

math (trig)
i have some problems doing trig the first one is: Show that cos(x/2) sin(3x/2) = ½(sinx + sin2x) i know that you are supposed to substitute all those trig function things in it but i kind of forgot how to the only that i can see substituting in is the

trig
I do not understand these problems. :S I'd really appreciate the help. Use trigonometric identities to transform the left side of the equation into the right side. cot O sin O = cos O sin^2 O  cos^2O = 2sin^2 O 1 (tan O + cot O)/tan O = csc^2 O

math
How would you establish this identity: (1+sec(beta))/(sec(beta))=(sin^2(beta))/(1cos(beta)) on the right, sin^2 = 1cos^2, that factor to 1cos * `1+cos, then the denominator makes the entire right side 1+cosB which is 1+1/sec which is 1/sec (sec+1) qed

trig
For each expression in column I, choose the expression from column II to complete an identity: Column I Column II 1. tanxcosx A. sin^2x/cos^2x 2. sec^2x1 B. 1/sec^2x 3. sec x/cscx C. sin(x) 4. 1+sin^2x D.csc^2xcot^2x+sin^2x 5. cos^2 x E. tanx I figured

TRIGONOMETRY *(MATHS)
Q.1 Prove the following identities: (i) tan^3x/1+tan^2x + cot^3x/1+cot^2 = 12sin^x cos^x/sinx cosx (ii) (1+cotx+tanx)(sinxcosx)/sec^3xcosec^3x = sin^2xcos^2x.

trigonometry
Can you draw the The solution for this: Establishing identities 1.) Sin²∅ (1+cot²∅) = 1 2.) (tan²B+1) cos²B = 1 3.) tan x  = sin x sec x 4.) 1 1  +  = 2csc²∅ 1+cos∅ 1cos Please help me, i cant understand it.

Math  Trig
I'm trying to verify these trigonometric identities. 1. 1 / [sec(x) * tan(x)] = csc(x)  sin(x) 2. csc(x)  sin(x) = cos(x) * cot(x) 3. 1/tan(x) + 1/cot(x) = tan(x) + cot(x) 4. csc(x)/sec(x) = cot(x)

trig
We are doing trig identities in school. I need help with these five: 1.1+sinx/1sinx=cscx+1/cscx1 2.tanx+sinx/1+cosx=tanx 3.sec^2x/sin^2x=1/sin^2x+1/cos^2x 4.tan^2x/1+tan^2x=1cos^2x 5.sinxsin^3x/cos^3x=tanx

Math Help
1) 1+cos(3t)/ sin(3t) + sin(3t)/( 1+ cos(3t))= 2csc(3t) 2) sec^2 2u1/ sec^2 2u= sin^2 2u 3) cosB/1 sinB= secB+ tanB

trig 26
simplify to a constant or trig func. 1. sec ²utan ²u/cos ²v+sin ²v change expression to only sines and cosines. then to a basic trig function. 2. sin(theta)  tan(theta)*cos(theta)+ cos(pi/2  theta) 3. (sec y  tan y)(sec y + tan y)/ sec y combine

Trigonometry
1.Solve tan^2x + tan x – 1 = 0 for the principal value(s) to two decimal places. 6.Prove that tan y cos^2 y + sin^2y/sin y = cos y + sin y 10.Prove that 1+tanθ/1tanθ = sec^2θ+2tanθ/1tan^2θ 17.Prove that sin^2wcos^2w/tan w sin w + cos w tan w =

trigonometry help me
6.Prove that tan y cos^2 y + sin^2y/sin y = cos y + sin y 10.Prove that 1+tanθ/1tanθ = sec^2θ+2tanθ/1tan^2θ 17.Prove that sin^2wcos^2w/tan w sin w + cos w tan w = cos wcot w cos w 23.Find a counterexample to shows that the equation sec a – cos

Math(Please check)
Use the fundamental identities to simplify the expression. tan^2 Q / sec^2 Q sin^2/cos^2 / 1/cos^2 = sin^2 / cos^2 times cos^2 / 1 = The cos^2 cancels out so sin^2 is left. Is this correct?

Trig Identities
Proving identities: 1) 1+ 1/tan^2x = 1/sin^2x 2) 2sin^2 x1 = sin^2x  cos^2x 3) 1/cosx  cosx = sin x tan x 4) sin x + tan x =tan x (1+cos x) 5) 1/1sin^2x= 1+tan^2 x How in the world do I prove this...please help... I appreciateyour time thankyou soo

pre cal
Use identities to simplify each expression. sin(x)+cos^2(x)/sin(x) = ? tan^3(x)−sec^2(x)tan(x)/cot(−x) = ? sin^4(x)−cos^4(x) =?

Pre Calculus
Use one of the identities cos(t + 2ðk) = cos t or sin(t + 2ðk) = sin t to evaluate each expression. (Enter your answers in exact form.) (a) sin(17ð/4) (b) sin(−17ð/4) (c) cos(17ð) (d) cos(45ð/4) (e) tan(−3ð/4) (f) cos(7ð/4) (g) sec(ð/6+2ð)

Trigonometry
Prove the following trigonometric identities. please give a detailed answer because I don't understand this at all. a. sin(x)tan(x)=cos(x)/cot^2 (x) b. (1+tanx)^2=sec^2 (x)+2tan(x) c. 1/sin(x) + 1/cos(x) = (cosx+sinx)(secx)(cscx) d. tan^2 (x)(1+1/tan^2 x)

trig
Third time is the charm? I'll try again. Could someone show me how, ( sin (x/2) /( 2 sin (x/2) + cos (x/2)) is an alternate representation for, 1 / ( 4 tan (x/2) + 2 ) TIA Carol This doesn't require the solving of any equations. For example, ( same

math
I have a question I have been working on since yesterday and I am not making this up. I couldn't get the right answer. If sin theta = 2/3, which of the following are possible? A: cos theta= the sqr rt of 5/3 and tan theta =2/3. B: sec theta = 3/the sqr

Precalculus
Verify the identities. Cos^2x  sin^2x = 2cos^2x  1 When verifying identities, can I work on both side? Ex. 1  sin^2x  sin^2x = 1  2sin^2x 1  2sin^2x = 1  2sin^2x

Trigonometry
Show that the following are not trigonometric identities 1.tan 2x = 2tan x 2. sec x= sqr rt 1+tan^2 x 3. sin(x+y)=sin x +sin y

Trig
Solve in terms of sine and cosine: sec(x) csc(x) sec(x) sin(x) so far I have: 1/cos(x) 1/sin(x)  1/cos(x) sin(x) I am not sure where to go to from there. The book says the answer is cot(x) or cos(x)/sin(x) Thank you in advance.

Mathematics  Trigonometric Identities
Let y represent theta Prove: 1 + 1/tan^2y = 1/sin^2y My Answer: LS: = 1 + 1/tan^2y = (sin^2y + cos^2y) + 1 /(sin^2y/cos^2y) = (sin^2y + cos^2y) + 1 x (cos^2y/sin^2y) = (sin^2y + cos^2y) + (sin^2y + cos^2y) (cos^2y/sin^2y) = (sin^2y + cos^2y) + (sin^2y +

more trig.... how fun!!!!
if you can't help me with my first question hopw you can help me with this one. sec(x)/csc(x)=tan(x) thanx to anyone who can help From the definition of the sec and csc functions, and the tan function, sec(x)/csc(x) = sin(x)/cos(x) = tan(x) However,

Trig
The question is: Set up a 2 column proof to show that each of the equations is an identity. Transform the left side to become the right side. a. (tan + cot)^2 = sec^2 + csc^2 I'm having trouble with this. b. (cos + sin)/cos + (cos  sin)/sin = csc sec I'm

Trigonometry
Please review and tell me if i did something wrong. Find the following functions correct to five decimal places: a. sin 22degrees 43' b. cos 44degrees 56' c. sin 49degrees 17' d. tan 11degrees 37' e. sin 79degrees 23'30' f. cot 19degrees 0' 25'' g. tan

Math
1. Find y'(x) when xsecy  3y sinx = 1 a) (3ycosx  sec y) / (xsec^2y  3sinx) b) (3cosx  sec x) / (xsecytany  3sinx) c) (3ycosx  sec y) / (xsecytany  3sinx) d) (3ycosx  secytany) / xsec^2y  3sinx) This is what I did: xsecy  3y sinx = 1 => sec y + x

Trig Identities
Prove the following identities: 13. tan(x) + sec(x) = (cos(x)) / (1sin(x)) *Sorry for any confusing parenthesis.* My work: I simplified the left side to a. ((sinx) / (cosx)) + (1 / cosx) , then b. (sinx + 1) / cosx = (cos(x)) / (1sin(x)) I don't know how

Calculus
Okay so I have a question on my assignment that says: You are given that tan(y) = x. Find sin(y)^2. Express your answer in terms of x. I know its derivatives, and I've tried taking the derivatives of both etc, and got them both to come out as cos(y)^2,

Confused! PreCal
Verify that each equation is an identity.. tan A= sec a/csca I have notes (i wasn't here that day and teacher refuses to reteach) but I don't understand them here is the notes... Problem w/ same directions: Cos x= cotx/csc x = Cosx/Sin x / 1/sinx = cosx I

Trigonometry
Prove the following identities: 1. (tan theta  sin theta)^2 + (1cos theta)^2 = (1sec theta) ^2 2. (12cos^2 theta) / sin theta cos theta = tan theta  cot theta 3. (sin theta + cos theta ) ^2 + (sin theta  cos theta ) ^2 = 2 Thank you so much! :)

Maths
Please help Trigonometric identities proof (cot^2(x)(sec(x)1))/1+sin(x)=(sec^2(1sin(x))/1+sec(x) Many Thanks

Math  help really needed
Prove each idenity. 1+1/tan^2x=1/sin^2x 1/cosxcosx=sinxtanx 1/sin^2x+1/cos^2x=1/sin^2xcos^2x 1/1cos^2x+/1+cosx=2/sin^2x and (1cos^2x)(1+1/tan^2x)= 1 I haven't even gotten 'round to sny of the quedtions because the first one is just so hard. I'm not

Calculus
s=çdx/(4+5cos x). By using tsubstitution, i.e. t=tan(x/2) we get cos x=(1t^2)/(1+t^2) and dx=2dt/(1+t^2). Substituting in s and simplifying, we get s= 2çdt/4(1+t^2)+5(1t^2)=2çdt/(9t^2). Using standard result çdx/(a^2x^2)=1/a*arctanh (x/a)

Studying for math test
Multiply; then use fundamental identities to simplify the expression below and determine which of the following is not equivalent. (sin x + cos x) ^2 a. 1+2sinxcosx b. sec^2x−tan^2x+2cosxsinx c. sec x + 2 sin x/sec x d. sin^2x+cos^2x e. 1+2cos (pi/2 x)

Trigonometry
Verify the identities. 1.) SIN[(π/2)X]/COS[(π/2)X]=COT X 2.) SEC(X)/CSC(X)= TAN X 3.) (1 + SIN Y)[1 + SIN(Y)]= COS²Y 4.) 1 + CSC(θ)/COS(θ) + COT(θ)= SEC θ (Note: Just relax through verifying/solving these nice fun looking math problems!

trig
how do you start this equation i've been tryng it for 20min. sec^6x(secxtanx)sec^4x(secxtanx)=sec^5xtan^3x ec^6x(secxtanx)sec^4x(secxtanx)=sec^5xtan^3x Factor out a sec^5 tan and divide thru. Left is sec^2 x = Tan^2 x Then this should reduce to sin^2 x =

Trigonometry desperate help, clueless girl here
2. solve cos 2x3sin x cos 2x=0 for the principal values to two decimal places. 3. solve tan^2 + tan x1= 0 for the principal values to two decimal places. 4. Prove that tan^2(x) 1 + cos^2(x) = tan^2(x) sin^2 (x). 5.Prove that tan(x) sin(x) + cos(x)=

PreCalculus
I don't understand,please be clear! Prove that each equation is an identity. I tried to do the problems, but I am stuck. 1. cos^4 tsin^4 t=12sin^2 t 2. 1/cos s= csc^2 s  csc s cot s 3. (cos x/ sec x 1) (cos x/ tan^2x)=cot^2 x 4. sin^3 z cos^2 z= sin^3

trig help much appreciated! :))
1. Find the complete exact solution of sin x = . 2. Solve cos 2x – 3sin x cos 2x = 0 for the principal value(s) to two decimal places. 3. Solve tan2 x + tan x – 1 = 0 for the principal value(s) to two decimal places. 4. Prove that tan2 – 1 + cos2

trignonmetry
6. Prove that tan λ cos^2 λ + sin^2λ/sin λ = cos λ + sin λ 10. Prove that 1+tanθ/1tanθ = sec^2θ+2tanθ/1tan^2θ 17.Prove that sin^2wcos^2w/tan w sin w + cos w tan w = cos wcot w cos w 23. Find a counterexample to shows that the equation sec

calculus trigonometric substitution
∫ dx/ (x^2+9)^2 dx set x = 3tan u dx = 3 sec^2 u du I = 3 sec^2 u du / ( 9 tan^2 u + 9)^2 = 3 sec^2 u du / ( 81 ( tan^2 u + 1)^2 = sec^2 u du / ( 27 ( sec^2 u )^2 = du / ( 27 sec^2 u = 2 cos^2 u du / 54 = ( 1 + cos 2u) du / 54 = ( u + sin 2u / 2) / 54 =

PreCalculus
Prove that each equation is an identity. I tried to do the problems, but I am stuck. 1. cos^4 tsin^4 t=12sin^2 t 2. 1/cos s= csc^2 s  csc s cot s 3. (cos x/ sec x 1) (cos x/ tan^2x)=cot^2 x 4. sin^3 z cos^2 z= sin^3 z  sin^5 z

calculus II
∫ tan^2 x sec^3 x dx If the power of the secant n is odd, and the power of the tangent m is even, then the tangent is expressed as the secant using the identity 1 + tan^2 x = sec^2 x I thought that since tan is even and sec is odd, we have to put this in

MATH
Hi, I really need help with these questions. I did some of them halfway, but then I got stuck. Would you please help me? Thank you so much. Prove the identity.... 1. sec x + tan x(1sin x/cos x)=1 1/cos x + sin x/cos x(cos^2 x/cos x)=1 1+sin x/cos

precalculus
For each of the following determine whether or not it is an identity and prove your result. a. cos(x)sec(x)sin^2(x)=cos^2(x) b. tan(x+(pi/4))= (tan(x)+1)/(1tan(x)) c. (cos(x+y))/(cos(xy))= (1tan(x)tan(y))/(1+tan(x)tan(y)) d.

trig
Hi there! I NEED SERIOUS HELP, PLEASE!!! i have such a hard time with verifying identities! The question is: [(sin(theta/2)) / csc(theta/2)] + [(cos (theta/2) / sec(theta/2)] = 1 I have a few ideas on how to solve this, but am mainly not sure how to get

Math Trig
1. Determine the exact value of cos^1 (pi/2). Give number and explanaton. 2. Determine the exact value of tan^1(sq. root 3). with explanation. 3. Determine exact value of cos(cos^1(19 pi)). with explanation. 4. Determine the exact value of sin(sin^1(20

trigo math
7. Prove that tan B sin B + cos B = sec B. 11. Prove that tanλ cos^2λ +sin^2λ/sinλ = cos λ + sin λ. 12. Prove that 1+tanθ/1+tanθ = sec^2θ+2tanθ/ 1tan^2θ. 21. Prove that sin^2wcos^2w/ tan w sin w + cos w tan w = cos w – cot w cos w.

Trigonometry
Prove ((sec^2(x))(sec^2(x)+1)/sin^2(x) +csc^4(x)tan^2(x)*cos^2(x) = (sec^4(x))/sin^2(x) + sec^2(x)*csc^4(x)  sin^2(x) is an identity.

Trigonometry
Verify whether this is an identity: ((sec^2(x))(sec^2(x)+1))/sin^2(x) + csc^4(x)  tan^2(x)*cos^2(x) = (sec^4(x))/sin^2(x) + sec^2(x)*csc^4(x)  sin^2(x)

Maths Calculus Derivatives
Find the first derivative for the following functions 1) f(x) = sin(cos^2x) cos(sin^3x) 2) f(x) = ( tan 2x  tan x ) / ( 1 + tan x tan 2x ) 3) f(x) = sin { tan ( sqrt x^3 + 6 ) } 4) f(x) = {sec^2(100x)  tan^2(100x)} / x

Precalculus check answers help!
1.) Find an expression equivalent to sec theta sin theta cot theta csc theta. tan theta csc theta sec theta ~ sin theta 2.) Find an expression equivalent to cos theta/sin theta . tan theta cot theta ~ sec theta csc theta 3.) Simplify (tan^2 theta +

math (trig)
Find sin(x/2) if sin(x)= 0.4 and 3pi/2 < or equal to (x) < or equal to 2pi Let's use cos 2A = 1  2sin2 A and we can match cos x = 1  2sin2 (x/2) so we will need cos x we know sin x = .4 and x is in the fourth quadrant, so the cosine will be positive.

Math
Prove each identity: a) 1cos^2x=tan^2xcos^2x b) cos^2x + 2sin^2x1 = sin^2x I also tried a question on my own: tan^2x = (1 – cos^2x)/cos^2x R.S.= sin^2x/cos^2x I know that the Pythagorean for that is sin^2x + cos^2x That's all I could do.

Math  help really needed
I'm sorry to double post; I don't want to seem impatient, but I really need help with this. Prove each idenity. 1+1/tan^2x=1/sin^2x 1/cosxcosx=sinxtanx 1/sin^2x+1/cos^2x=1/sin^2xcos^2x 1/1cos^2x+/1+cosx=2/sin^2x and (1cos^2x)(1+1/tan^2x)= 1 I haven't

Trig
Are any of these three problems identities? 1. Cos^2xsin^2x=12sin^2x 2. Sinxsecx=cosxcscx 3. Sec^4xtan^4/sec^2x=1+sin^2x If so, how can you conclude that any of them are identities?

Maths
Question : Integrate [x/(1+(sin a*sin x))] from 0 to pi My first thought was to apply integrate f(x) dx= f(ax) dx method Which simplified the integral into; 2I = integrate [pi/(1+(sin a*sin x))] dx , cancelling out x Then I made the integral into the form

Trigonometry
Verify/Solve the identities. 1.) SIN^1/2 X COS XSIN^5/2 X COS X 2.) Long problem, but it's fun to solve! SEC^6 X(SEC X TAN X)SEC^4 X(SEC X TAN X)

Trigonometry
Hello all, In our math class, we are practicing the trigonometric identities (i.e., sin^2(x)+cos^2(x)=1 or cot(x)=cos(x)/sin(x). Now, we are working on proofs that two sides of an equation are equal (for example, sin(x)*csc(x)=1;

Math
Trigonometry Identities problem: Prove the following; (tan^2x)(cos^2x) = (sec^2x  1)(1sin^4x) ÷ (1+sin^2x)

Mathematics
Prove the following trigonometric identities by showing that the lefthand side is equivalent to the righthand side. a) sin(t)/1cos(t) + 1cos(t)/sin(t) = 2sin(t)/1cos^2(t) b) 2tan(t)tan(t)(2sin^2(t))/sin(t)*cos(t) =

Math
Prove these identites I really need help with these I don't understand how to do them !!!! sin^2+tan^2=sec^2cos^2 sin^2 sec^2 +sin^2=tan^2+sin^2

math
Prove these identites I really need help with these I don't understand how to do them !!!! sin^2+tan^2=sec^2cos^2 sin^2 sec^2 +sin^2=tan^2+sin^2

math
Prove these identites I really need help with these I don't understand how to do them !!!! sin^2+tan^2=sec^2cos^2 sin^2 sec^2 +sin^2=tan^2+sin^2

Precal
I do not understand how to do this problem ((sin^3 A + cos^3 A)/(sin A + cos A) ) = 1  sin A cos A note that all the trig terms are closed right after there A's example sin A cos A = sin (A) cos (A) I wrote it out like this 0 =  sin^6 A  cos^6 A +

precalc
Given that sec 3π/10 ≈ 17/10 and csc 3π/10 ≈ 17/14, find the following: 1. sin 3π/10 ≈ 14/17 (is this one correct) 2. csc 43π/10 ≈ 3. sec 2π/10 ≈ 4. cot 12π/10 ≈ 5. tan π/5 ≈ 6. sin 7π/10 ≈ 7. cos 13π/10 ≈ 8. tan 33π/10 ≈ i

Trig Identities
Please help...I'm not understanding trig identities and how to manipulate and express these two problems in their associated functions. Thanks a)Express as a function of cos (theta) 2 sin^2(theta)  1 b)Express as a function of sin (theta) or cos (theta)

TRIG!
Posted by hayden on Monday, February 23, 2009 at 4:05pm. sin^6 x + cos^6 x=1  (3/4)sin^2 2x work on one side only! Responses Trig please help!  Reiny, Monday, February 23, 2009 at 4:27pm LS looks like the sum of cubes sin^6 x + cos^6 x = (sin^2x)^3 +

Calculus
I wanted to confirm that I solved these problems correctly (we had to convert the polar curves to Cartesian equations). 1.rcos(theta)=1 x=1 2.r=2*sin(theta)+2*cos(theta) r^2=2rsin(theta)+2rcos(theta) x^2+y^2=2y+2x (a little unsure what do next if this is

Trigonometry
Prove the following identities: 1. (tan theta  sin theta)^2 + (1cos theta)^2 = (1sec theta) ^2 2. (12cos^2 theta) / sin theta cos theta = tan theta  cot theta 3. (sin theta + cos theta ) ^2 + (sin theta  cos theta ) ^2 = 2 Thank you so much! :)

Math
for (sec x 1)(sec x + 1) = tan^(2) x so far I got up to: (sin^(2)x / cos x) (sin^(2)x / cos x) what would the next step be? steps too please

trigonometry
How do you work these out? sec u 1 / 1cos u = sec u sec xcos x= sin x tan x 1/sin x  1/csc x= csc x  sin x

verifying trigonometric identities
How do I do these problems? Verify the identity. a= alpha, b=beta, t= theta 1. (1 + sin a) (1  sin a)= cos^2a 2. cos^2b  sin^2b = 2cos^2b  1 3. sin^2a  sin^4a = cos^2a  cos^4a 4. (csc^2 t / cot t) = csc t sec t 5. (cot^2 t / csc t) = csc t = sin t

Calculus
I'm struggling some with the us of trigonomic properties. The problem is integral sin(2x)sec(x) dx and I don't understand how sin(2x)sec(x) simplifies into 2sin(x).

Math
Prove Trig. Identities 1. sec è (sec è  cos è)= tan^2 è 2. tan^2 è (1 + cot^2 è) = sec^2 è

Math
Solve each equation for all real values of x. 7.) 3 cos 2x  5 cos x = 1 8.) 2 sin^2 x5 sin x + 2 = 0 9.)3 sec^2  4 = 0 10.) tan x (tan x1) = 0